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First isomorphism theorem: Difference between revisions

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Let <math>G</math> and <math>H</math> be [[Group|groups]] and <math>f\colon g\to H</math> a group homomorphism. Then,
Let <math>G</math> and <math>H</math> be [[Group|groups]] and <math>f\colon g\to H</math> a group homomorphism. Then,


* The kernel of <math>f</math> is a normal subgroup of <math>G</math>.
* The kernel of <math>f</math>, <math>\ker f\trianglelefteq G</math> is a normal subgroup of <math>G</math>.
* The image of <math>f</math> is a subgroup of <math>H</math>.
* The image of <math>f</math>, <math>\operatorname{im}f<G</math> is a subgroup of <math>H</math>.


* <math>G/\ker f \cong \operatorname{im} f</math>.
* <math>G/\ker f \cong \operatorname{im} f</math>.

Revision as of 20:56, 10 April 2026

The first isomorphism theorem is a fundamental result in abstract algebra that describes the relationship between a homomorphism, its kernel, and its image. The theorem appears uniformly across algebraic structures such as groups, rings, and modules, and serves as a prototype for many structural results in algebra. Specifically, given a homeomorphism, the quotient of its domain by its kernel is isomorphic to its image.

Group theory

Statement

Let G and H be groups and f:gH a group homomorphism. Then,

  • The kernel of f, kerfG is a normal subgroup of G.
  • The image of f, imf<G is a subgroup of H.
  • G/kerfimf.