First isomorphism theorem: Difference between revisions
Appearance
No edit summary |
|||
| Line 6: | Line 6: | ||
Let <math>G</math> and <math>H</math> be [[Group|groups]] and <math>f\colon g\to H</math> a group homomorphism. Then, | Let <math>G</math> and <math>H</math> be [[Group|groups]] and <math>f\colon g\to H</math> a group homomorphism. Then, | ||
* The kernel of <math>f</math> is a normal subgroup of <math>G</math>. | * The kernel of <math>f</math>, <math>\ker f\trianglelefteq G</math> is a normal subgroup of <math>G</math>. | ||
* The image of <math>f</math> is a subgroup of <math>H</math>. | * The image of <math>f</math>, <math>\operatorname{im}f<G</math> is a subgroup of <math>H</math>. | ||
* <math>G/\ker f \cong \operatorname{im} f</math>. | * <math>G/\ker f \cong \operatorname{im} f</math>. | ||
Revision as of 20:56, 10 April 2026
The first isomorphism theorem is a fundamental result in abstract algebra that describes the relationship between a homomorphism, its kernel, and its image. The theorem appears uniformly across algebraic structures such as groups, rings, and modules, and serves as a prototype for many structural results in algebra. Specifically, given a homeomorphism, the quotient of its domain by its kernel is isomorphic to its image.
Group theory
Statement
Let and be groups and a group homomorphism. Then,
- The kernel of , is a normal subgroup of .
- The image of , is a subgroup of .
- .